Question

A 1300 kg sports car accelerates from rest to 95 km/h in 7.4 s. What is the average power delivered by the engine?

Answer 1

Power = work done / time

work done = Change in K.E

hope this helps/......

Answer 2

\[F=m*a\] to find a use \[a=\frac{ V }{ t }=\frac{ 26.38 }{ 7.4 }=3.566m/s^2\] now
F= 1300*3.566=4635.88N
now find the distance covered in 7.4 seconds
\[D=ut+\frac{ 1 }{ 2 }at^2\]
u=0 , D= 0.5*3.566*(7.4)^2=97.637m
now work done = F*D=4635.88*97.637=452633.786 j
finally power = w/t= 452633.768/7.4=61166.727 Watts
looks like its bugati veyron lol

Answer 3

damn :( lol

Answer 4

work done = Change in K.E

=1/2 m v^2 - 0

Answer 5

correct