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\[\int\limits_{0}^{3}\int\limits_{0}^{2}(4-y ^{2})dydx\]
simple first solve this \[\int\limits_{0}^{2}(4-y^2)dy\] once you find the solution which we will call "Z" do the integral \[\int\limits_{0}^{3}Z dx\]
What is the first step of integral? Of \[(4-y ^{2})\]?
... if you're doing double integrals, how do you not know how to integrate...
The first step this time is a bit confusing.
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\[\int\limits_{0}^{2}(4-y^2)dy=\int\limits_{0}^{2}4dy-\int\limits_{0}^{2}y^2 dy\]
Ok, I think I can take it from here.
x and y are variables, they can be replaced with whatever variables you choose if it helps you solve the integral
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