Question

Step by Step help? ;D

Answer 1

question??

Answer 2

\[y=\frac{ \cos(x) }{ x-2^{x} }\]

finding dy/dx

Answer 3

I know I use the quotient rule

Answer 4

the equation for finding slopes of such equations are

dy/dx = u'(v) - v'u/(v^2), with u being the numerator and v being the denominator and u' and v' being the derivative of each u and v

Answer 5

oh lol don't know how to find the derivative for the denominator

Answer 6

nor do I... that's what I'm stuck on

Answer 7

maybe its 1 - x2^(x-1)

Answer 8

the same way u wud treat a regular exponent

Answer 9

1-2^{x}ln(2)

Answer 10

d/dx(x-2^x)=1-2^x(ln(-2)

Answer 11

I figured it out, thank you guys!

Answer 12

so whats the derivative of the bottom?

Answer 13

the answer is.. \[\frac{ (-sinx)(x-2^{x})-(\cos(x))(1-2^{x}\ln(2)) }{ (x-2^{x})^{2} }\]

Answer 14

lol wolfram alpha?

Answer 15

uhm no, the answer in my study guide thank you very much.

Answer 16

you don't find the derivative of the denom? it stays like that lol

Answer 17

u need to find it for the top

Answer 18

and I did lol!

Answer 19

nice