Question

Solve without a calculator

Answer 1

\[\[\huge 4\tan^2-\sec^2x=0\]\]

Answer 2

0<x<2pi

Answer 3

@UnkleRhaukus

Answer 4

\[4\tan^2 (x)-\sec^2 (x)=0\]

Answer 5

yup

Answer 6

\[\tan(\theta)=\frac{\sin(\theta)}{\cos(\theta)}\]\[\sec(\theta)=\frac{1}{\cos(\theta)}\]

Answer 7

•take the sec term to the other side of the equation,

•substitute the above definitions into your equation,

•multiply by the denominator

•divide by 4

•take the sqrt of both sides ,

•take the inverse trig function to isolate x

Answer 8

tell me if you get stuck.

Answer 9

\[4\frac{ \sin^2x }{ \cos^2x }-\frac{ 1 }{ \cos^2x }=0\]

Answer 10

what do i do next

Answer 11

multiply by cos^2

Answer 12

to subtract the two ??

Answer 13

(2sinx+1)(2sinx-1) / cos^2x

Answer 14

how did that happen?

Answer 15

idk im guessing :S

Answer 16

start again and follow the •'s

Answer 17

okay

Answer 18

i'm going to be honest, im confused

Answer 19

by following the checlist this is what im getting sinxcosx-sinx

Answer 20

May I suggest another approach?

Answer 21

...

Answer 22

my teacher has a completely different way im confuseeed

Answer 23

well im sure there are many different ways ,

Answer 24

1 + tan^2 x = sec^2 x

tan^2 x = sec^2 x - 1

Answer 25

i dont like that way as much as i like the way i have outlined , but that is opinion

Answer 26

4 ( sec^2 x - 1) - sec^2 x = 0

4 sec^2 x - 4 - sec^2 x = 0

3 sec^2 x = 4

sec x = 2/ sqrt (3)

Answer 27

i am only allowed to have cos and sin in my answers

Answer 28

Lol.....u shuld have Mentioned that in the question...)

Answer 29

Steps:
1. rearrange and isolate the unknown
2. move everything to one since, set equal to zero
3. use the zero principle
4. use inverse trig to find the angle
5. use CAST or ASTC to adjust answers
@Yahoo! i know sorry ! :$