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\[\LARGE y=10^{5\log _{10}x} \]
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\[\LARGE y=10^{5\log _{10}x }\]
Attempt: \[\LARGE logy=5logxlog10\]
\[\LARGE \frac{dy}{dx}=ylog10 \frac{5}{x}\]
\(\huge a^{\log_ax}=x\)
:O
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\(\LARGE y=10^{5\log _{10}x }=\LARGE 10^{\log _{10}x^5 }=x^5\)
:O
came across it first time o.o
if you want to prove that, take log on both sides of that equation, and use log_p q = log q/log p
I took logs on my attempt^ are u referring to that?
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i was saying if you want proof of that 5th ptoperty which i used here also, u take log for this Q, u directly get y=x^5
\[\LARGE y=10^{5logx} \]
5 log x = log (x^5)
\[\LARGE 5\log _{10}xlog10\] that is what we get on taking logs
why did u take log for this Q ?
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:o
i see !
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