Can someone check my work?
1. A plane travels from Orlando to Denver and back again. On the five-hour trip from Orlando to Denver, the plane has a tailwind of 40 miles per hour. On the return trip from Denver to Orlando, the plane faces a headwind of 40 miles per hour. This trip takes six hours. What is the speed of the airplane in still air? Orlando to Denver 5h with plane tailwind of 40 mph. Distance 1 (d1) = distance from Orlando to Denver. Distance 2 (d2) = distance from Denver to Orlando. Formula to use: D= rt What we know: - d1 = (r+40) (5) - d2 = (r-40) (6) - d1 = d2 - (r+40) (5) = (r-40) (6) Distribute the 5 and 6. - 5r + 200 = 6r – 240 Subtract 5r from 6r - 200 = r – 240 Add 240 to 200 - 440 = r The speed of the airplane in still air if 440 mph.
seems alright to me...
just write 440 miles per hour
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