Question

equation of the tangent line to the curve y=e^(1-x)+3/(x^2)+1

Answer 1

at which point?

Answer 2

Stfu b!tch

Answer 3

@Mathmuse closed intereval (0,3)

Answer 4

the equation will change based on which point on the interval you are evaluating because the slope at each point (the derivative) will be different

Answer 5

Do you even lift

Answer 6

?
\[\large y= e^{(1-x)}+\frac{3}{x^2+1}\]

Answer 7

the e^(1-x) is on the line with the +3

Answer 8

@Mathmuse

Answer 9

stfu

Answer 10

\[\large y= \frac{e^{(1-x)}+3}{x^2+1}\]

Answer 11

yes, need the equation of the tangent line at (1,2)

Answer 12

ahhh..ok (1,2)
you'll need to fill in the following form
\[\large y - y_1 = m(x-x_1)\]
where the values with subscripts can be those two points (ie x1 = 1, y1 = 2)
and the m is the slope. this is found by taking the derivative of the function and subbing those same two x,y values

Answer 13

@ssaid2 clear as mud?