the lim as x approaches positive infinity of (x-(1/2x))/(2x+6x) is?

Question

anonymous · Answer

how do you solve for an infinite limit?

anonymous · Answer

$$\lim_{x \rightarrow \infty}\frac{x-\frac{1}{2}x}{2x+6x}=\lim_{x \rightarrow \infty}\frac{\frac{1}{2}x}{8x}=\lim_{x \rightarrow \infty}\frac{\frac{1}{2}}{8}=\frac{1}{16}$$

anonymous · Answer

very easy you should just consider the high rate of varaiable in nominator and denominator
so answer is (1/2x)/8x=1/16

anonymous · Answer

Okay so... I messed up the problem.  Here it is $$\lim_{x \rightarrow \infty}\frac{ x- \frac{ 1 }{ 2x } }{ 2x+ \frac{ 1 }{ 6x } }$$

anonymous · Answer

HAHA xD

anonymous · Answer

I was wondering why your work was so much simpler than what I thought, I realized I messed up.

anonymous · Answer

That's why everbody has to use $$\mathrm{LaTeX}$$
The answer is 1/2 and the And the procediment is similar.

anonymous · Answer

I've got it now! Thank you!