Question

When solving systems of equations you should find the easiest way to use based on the equation that you are working with.

For this equation the easiest I could find was elimination

1st we need to salve for “x”
6x – 4y = 54

–9x + 2y = –69 You need to multiply by 2 on this equation and then combine the two equations.

3x = -15

X=5

2nd we need to solve for “y”
6x - 4y = 54

-9x + 2y = -69

6y= 5

Y= 1.2


Elimination IS the easiest to use.

Answer 1

these are your simultaneous equations?

\[6x – 4y = 54\qquad(i)\]
\[–9x + 2y = –69\qquad(ii)\]

Answer 2

\[6x-4y=54\]\[-9x+2y=-69\]\[6x-4y+2(-9x+2y)=54+2(-69)\]\[6x-4y-18x+4y=54-138\]\[-12x=-84\]\[x=\frac{ -84 }{ -12 }=7\]

Answer 3

all it says is math processing error

Answer 4

reload

Answer 5

ok I did

Answer 6

yes Un kleRhakkus

Answer 7

in reply to your first reply

Answer 8

Aylin has solved using the method you suggested but as you can see you made some mistakes in your working

Answer 9

Yes I did thank you guys very much :)

Answer 10

i might suggest a slight variation

\[6x–4y=54\qquad(i)\]\[–9x+2y=–69\qquad(ii)\]

divide (i) by 2
\[3x–2y=27\qquad(iii)\]
now add (ii) and (iii)

\[(–9x+2y)+(3x–2y)=(–69)+(27)\]
\[–6x=-42\]\[x=\frac{-42}{-6}=7\]

Answer 11

Dividing by 2 is probably easier. I multiplied the second instead so it would be easier for EvonHowell to follow what I did and see where his mistake was made.

Answer 12

well, Thank you guys soooo much :)

Answer 13

Glad to help. :)

Answer 14

:)