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Mathematics 13 Online
OpenStudy (anonymous):

I need help on the problem shown at http://pbckt.com/pK.uZbDhl .

OpenStudy (anonymous):

@ghazi

OpenStudy (anonymous):

how many halves can you take from each candy so that you always have 3 of each?

OpenStudy (ghazi):

\[1\frac{ 1 }{ 2}=\frac{ 2*1+1 }{ 2 }=\frac{ 3 }{ 2 }\] similarly 2 1/4= 9/4 and she adds 1/2 cup of peppermint so total of \[\frac{ 3 }{ 2 }+\frac{ 9 }{ 4 }+\frac{ 1 }{ 2 }=\frac{ 6+9+2 }{ 4 }=\frac{ 17 }{ 4 }\] \[\frac{ 1 }{ 2 } \] cups in one bag so 1 cup in 1/1/2= 2 bags there fore 17/ cups in 17/4 * 2 = 8.5 bags or you can say 9 bags

OpenStudy (anonymous):

lemme read all of that.

OpenStudy (ghazi):

sure

OpenStudy (anonymous):

why 6+9+2?

OpenStudy (ghazi):

take the LCM let me show you

OpenStudy (anonymous):

mk.

OpenStudy (anonymous):

the lcm wud b 4

OpenStudy (ghazi):

\[\frac{ 3 }{ 2 }+\frac{ 9 }{ 4 }+\frac{ 1 }{ 2 }=\frac{ 3*2 +9+1*2}{ 4 }=\frac{ 6+9+2 }{ 4 }=\frac{ 17 }{ 4 }\]

OpenStudy (ghazi):

yes it would be 4

OpenStudy (anonymous):

so.. lemme c. one sec. ill work it out

OpenStudy (ghazi):

cool

OpenStudy (anonymous):

or attemot to at least

OpenStudy (anonymous):

attempt*

OpenStudy (anonymous):

mk. so, 17/4?

OpenStudy (ghazi):

of course miss old lady

OpenStudy (anonymous):

Okay. Do me a favor and call me by my first name, will ya?

OpenStudy (anonymous):

Well, then user12.

OpenStudy (ghazi):

oop sorry

OpenStudy (anonymous):

'tis fine,

OpenStudy (ghazi):

tis?

OpenStudy (anonymous):

'tis = it is

OpenStudy (ghazi):

cool

OpenStudy (anonymous):

yup.

OpenStudy (ghazi):

:D

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