Question

How would i find the solution to this equation? log16 32 = x + 2.

Answer 1

16 is the base

Answer 2

first we need the number for
\[\log_{16}(32)\]
i.e. we are trying to solve
\[16^y=32\]
since \(16=2^4\) and \(32=2^5\) this is the same as solving
\[2^{4y}=2^5\] so
\[4y=5\] and therefore\[ 9y=\frac{5}{4}\]
last job is to solve
\[\frac{5}{4}=x+2\]

Answer 3

typo there, should be \[y=\frac{5}{4}\]