simplify:
(x^2y^3z^6)^0

Question

simplify:
(x^2y^3z^6)^0

callisto · Answer

a^0 = 1

callisto · Answer

Hmm... Got it?

anonymous · Answer

no :( i hate this kind of stuff

callisto · Answer

That's a property of exponential function :|

anonymous · Answer

would you multiply all of the exponents by 1 and it would just be the same?

callisto · Answer

|dw:1355545292481:dw| Exponential function has this graph.. They (all) pass through (1,0)

anonymous · Answer

@sauravshakya helpppppp lol

callisto · Answer

$$(x^2y^3z^6)^0 = (x^{2\times 0})(y^{3\times 0})(z^{6\times 0}) = x^0y^0z^0=...$$

anonymous · Answer

so it would just be xyz?

callisto · Answer

a^0 = 1 ...  :|
So, x^0 =1... Guess what y^0 and z^0 are!

anonymous · Answer

1? lol would you multiply all those to still = 1 or would you add them all?

callisto · Answer

1...
$$x^0y^0z^0 = 1\times 1 \times 1$$

anonymous · Answer

ok thats what i thought

callisto · Answer

It's true when x, y, z >0

anonymous · Answer

uhg this is so confusing.. i would know this stuff if i was at school.. but i was sick the day we did this stuff

callisto · Answer

An easier way is to treat x^2y^3z^6 = a
And apply the properties a^0 =1 to get the answer immediately ...
Oh.. I'm sorry to hear that :(

anonymous · Answer

so the whole thing would = 1?

callisto · Answer

*property

Yes.

callisto · Answer

Same answer as you get from $(x^2y^3z^6)^0 = (x^{2\times 0})(y^{3\times 0})(z^{6\times 0}) = x^0y^0z^0=...$

anonymous · Answer

so i could say x,y,z = 1? or just 1

callisto · Answer

No! It's $(x^2y^3z^6)^0 =1$ 
That doesn't mean x, y, z =1 :\