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Factor by Grouping: 4z² + 12z - az - 3a
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In factoring by grouping, you factor the first two terms and then the last two.
So then the first two terms would come out to 4z(z + 3) ?
Yes, and the last two?
-a(z + 3)
Okay, so you have \(4z(z + 3) - a(z + 3)\). Can you factor that further?
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Nope, not that I can see. Unless I can do something with both (z+3)'s...
Yes, you can!
For example, you have \(ax + bx\). You may factor it so it becomes \((a + b)x\). The same way, you can always apply the trick to this one ;)
then in this case, I would replace x with (z + 3)? (4z - a)(z + 3)?
Yes!
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Much obliged!
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