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Mathematics 14 Online
OpenStudy (anonymous):

Can someone help, I need to find an equation for this graph.

OpenStudy (anonymous):

OpenStudy (nubeer):

asinx a is the highest amplitude

OpenStudy (anonymous):

Period is double, will have to work out, its not simply asinx.

OpenStudy (anonymous):

3sin(t/2)

OpenStudy (nubeer):

i dont think so one complete cycle is done in 2pi

OpenStudy (anonymous):

I believe its 4pi for the graph, one complete cycle is one up and one down.

OpenStudy (nubeer):

nop one complete cycle is done in 2pi

OpenStudy (nubeer):

its a sin wave and its done in 2pi it same like circle one complete round is 2pi

OpenStudy (anonymous):

this is why i am confused, lol

OpenStudy (anonymous):

You can have a sinusoid that ossicaltes faster/slower, which changes the period.

OpenStudy (nubeer):

ya i know .. u cant answer right if u dont know how the normal regular wave looks like

OpenStudy (anonymous):

You can plug the numbers in and work it out, shouldnt be too hard, asinx wouldnt work in this case either way.

OpenStudy (nubeer):

i know but one period is comeplete in 2 pi not 4 pi

OpenStudy (anonymous):

its periodic with two pi, and so is, 3sin(t/2) or x in this case.

OpenStudy (anonymous):

it however oscilates faster

OpenStudy (nubeer):

ok sorry read the graph wrong.

OpenStudy (nubeer):

couldnt saw where the 2pi is

OpenStudy (anonymous):

yup, no probs

OpenStudy (anonymous):

And it ossilates slower in this case, not faster, a correction on what I said previously.

OpenStudy (anonymous):

so is it y=3sin(5x) ? or am I way off?

OpenStudy (anonymous):

nope just y= 3sin(x/2)

OpenStudy (anonymous):

try plugging in numbers as well, that should help you see it better. Otherwise because it is slower than a reguar sinusoidal, you can simply put in the half there.

OpenStudy (anonymous):

ah, thank you.

OpenStudy (anonymous):

yup no problem

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