A question from my friend.
A pendulum clock which correct time at a point where g=980.0 cm/s" is found to loss 10 s per day at a higher altitude. Find the valueof g at the new location!

Question

A question from my friend. 
A pendulum clock which correct time at a point where g=980.0 cm/s" is found to loss 10 s per day at a higher altitude. Find the valueof g at the new location!

anonymous · Answer

Period is proportional to root L / g
If the period has increased (to make the clock go slow) by 10/(24.3600) then g must have decreased by the square of that fraction

anonymous · Answer

10 and 24.3600? Whats the number?

anonymous · Answer

A normal day is 24 x 3600 = 86400 s. Lets say the pendulum swings once to give this time so T = 86400s. At the higher altitude the gravity will be weaker so the period will be longer so the new period is 86410s. Since T = 2 PI root(L/g) we can find that Told / Tnew = root(gnew / gold) The only unknown in this equation is gnew so substitute and solve :)