By means of a rope, whose mass is negligible, two blocks are suspended over a pulley. The pulley can be treated as a uniform solid cylindrical disk. The downward acceleration of the 44kg block on the right side is observed to be one half of the acceleration due to gravity. Find the mass of the pulley. (on the left side hangs a 11 kg block.) NOTE.Tensions are different on the two side of the pulley.

Question

ksaimouli · Answer

@Callisto

ksaimouli · Answer

i just need the answer

ksaimouli · Answer

i got the equation as M = [2g(m₂ - m₁) - 2a(m₁ + m₂)] / a

ksaimouli · Answer

m1=11 and m2=44

anonymous · Answer

Yep. Your equation is absolutely right.
All you have to do now is plug the value of 'a', 'm1' and 'm2' :)

ksaimouli · Answer

am getting some thing like -242

vincent-lyon.fr · Answer

Your equation seems correct.
I find M = 22 kg

ksaimouli · Answer

Can u please show me

anonymous · Answer

substituting a=g/2 gives you
$$\Large M=2[m_2-3m_1]$$