How do i factor x^2 -5x + 4?
To factor, we want to find a pair of numbers that multiply together to get 4 and add together to get -5. First, observe that we have to add two numbers together to get -5. We multiply them together to get a positive 4. So, they're both going to be negative to fit these qualities.. We just have to list the negative factors of 4 and check which one adds up to -5: -1, -4; adds to -5 -2, -2; adds to -4 So, -1 and -4 are the factors: (x - 1)(x - 4). Check: (x - 1)(x - 4) = x(x - 4) - 1(x - 4) = x^2 - 4x - x + 4 = x^2 - 5x + 4 yes!
If that process isn't exactly clear, we can see how it makes sense in a general case: Let x - a and x - b be the factors of the quadratic. y = (x + a)(x + b) distributing = x(x + b) + a(x + b) distributing again = x^2 + bx + ax + ab combine like-terms = x^2 + (a + b)x + ab <--- the number next to x is the sum of a and b; and the constant at the end is the product of a and b.
So x^2 - 5x + 4 = x^2 + (a + b)x + ab; ab = 4 a + b = -5 Clearly a=-1 and b=-4 work here. :)
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