Question

What are the foci of the ellipse given by the equation 4x^2 + 9y^2 – 32x + 18y + 37 = 0?

(4, –1 ±√(5))

(4, –1 ±√(13))

(4 ±√(5) , –1)

(4 ±√(5) , 1)

Answer 1

hint:
Separate acording to each variable, x's and y's. and then use complete the square to get ur (y - #)^#

that way u can find the verteces, foci, and center.

Answer 2

can u show me how to do that?

Answer 3

\[(4x^2-32x) + (9y^2+18y)+37 = 0\]

Answer 4

sorry the ( ) + ( ) should be a - so that you can factor out.