What are the foci of the ellipse given by the equation 4x^2 + 9y^2 – 32x + 18y + 37 = 0?

(4, –1 ±√(5))

(4, –1 ±√(13))

(4 ±√(5) , –1)

(4 ±√(5) , 1)

Question

What are the foci of the ellipse given by the equation 4x^2 + 9y^2 – 32x + 18y + 37 = 0?

 (4, –1 ±√(5))

 (4, –1 ±√(13)) 

 (4 ±√(5) , –1)

 (4 ±√(5) , 1)

abb0t · Answer

hint:
Separate acording to each variable, x's and y's. and then use complete the square to get ur (y - #)^# 

that way u can find the verteces, foci, and center.

anonymous · Answer

can u show me how to do that?

abb0t · Answer

$$(4x^2-32x) + (9y^2+18y)+37 = 0$$

abb0t · Answer

sorry the ( ) + ( ) should be a - so that you can factor out.