Two triangles can be formed with the given information. Use the Law of Sines to solve the triangles. B = 29°, b = 26, c = 28
two answers are possible .because the congruency is not sure a,s,sproperty will not give unique answer. but any way you use sine formula to solve
A = 92.5°, C = 58.5°, a = 53.6; A = 87.5°, C = 121.5°, a = 53.6 A = 92.5°, C = 58.5°, a = 12.6; A = 87.5°, C = 121.5°, a = 12.6 A = 119.5°, C = 31.5°, a = 46.7; A = 2.5°, C = 148.5°, a = 2.3 A = 119.5°, C = 31.5°, a = 14.5; A = 2.5°, C = 148.5°, a = 14.5
sinA/a=sinB/b=sinC/c
im not clear on how to do that though:/
sinB/b=sinC/c solve for C
use cosine formula to solve for a.namely a^2=b^2+c^2-2bc cosA
here A will have two values according to A+B+C=180. Amay be accute or obtuse
ok so how would i plug in those numbers to the cos formula? im not good at this at all
i just dont know where the A comes from
first B may have two values as sin function is positive in 1st and 2nd quadrent. for both the values you solve for A.If B+C is more than 180 Bcan not be obtuse. sssthere is only one solution.
triangle prperty .Sum of aaaaangles in a triangle is 180 deg
ok so how can i find the answer? im still lost
first step use sinB/b=sinC/c
find sinC
i did and i got a weird decimal. how do i find sinC
sinB/b=.018
namely sinC=(c/b)sinB
WHAT IS YOUR SINc
sinC=.522?
REFER THE TRIGNOMETRY TABLE AND FIND THE ANGLE FOR WHICH .522 IS OCCURING
i dont see it on there
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