Question

write the single logarithm
4 log x-6 log (x+2)

Answer 1

i got log x^4(x+2)^6 not sure if right

Answer 2

log(a)-log(b)=log(a/b)

Answer 3

so what would you do after you get

log(x^4)-log(x+2)^6

Answer 4

noy real sure kinda guessing

Answer 5

its a law of logarithms

\[\log a- \log b=\log (a/b)\]

Answer 6

log x(x+2)^24

Answer 7

Divide them.

Answer 8

you mean like 24 log x/x+2

Answer 9

No i mean what we got earlier

log(x^4)-log(x+2)^6

Answer 10

not getting it thanks anyways

Answer 11

Its kinda like the other one you did just with a different law....

instead of log(a)+log(b)=log(a*b)

its log(a)-log(b)=log(a/b)

Answer 12

4 logx- 6/log(x+2) maybe

Answer 13

\[\huge \log (x^4/(x-6)^{2})\]

Answer 14

so thats how you write it as a single logarithm

Answer 15

Yes.

Here's the laws of logarithms you should get familiar with

Answer 16

ok thanks for the help