Question

cosxsinx=sin^2x, solve for x.

Answer 1

\[cosxsinx= \sin^2x\], solve for x!

Answer 2

if you had
xy = y^2 you would write it as
y^2 -x y= 0-
y( y-x)=0
and y=0 or y=x are the two answers

can you use this idea to solve your problem?

Answer 3

cosxsinx-sin^2x=0
sinx(cosx-sinx)=0
sinx=0 cosx-sinx=0
x=pi, 0 x= ?

Answer 4

for the second equatin
divide by cos x
1- sin x/ cos x =0
1 - tan x =0
tan x =1
so all angles that make tan x =1