please let me know if i'm correct :) i chose B Find the lateral area of the square pyramid shown, to the nearest whole number. A. 7294 yd2 B. 3192 yd2 C. 4758 yd2 D. 3647 yd2
B is incorrect, how did you get B?
perimeter*base/2
perimeter*height i mean , sorry
that's if you're dealing with a prism, not a pyramid
okay , so then what formula is correct for this problem?
if you draw in the slant height, you get what you see in blue
call that slant height s so s = slant height you can find the slant height if you look at the pyramid like this |dw:1355620862392:dw| this is what you would see if you look at the pyramid directly at once face (and not at the corner)...basically, you can only see one face
by the pythagorean theorem a^2 + b^2 = c^2 21^2 + 38^2 = s^2 441 + 1444 = s^2 s^2 = 441 + 1444 s^2 = 1885 s = ???
im confused on how to get the s now would i divide?
you take the square root to undo the square
s = sqrt(1885) s = ???
43.41?
so each triangular face looks like this |dw:1355621429131:dw|
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