Question

Solve the triangle.

a = 12, b = 22, C = 95°

Answer 1

c ≈ 26, A ≈ 27.6°, B ≈ 57.4°

c ≈ 26, A ≈ 54.4°, B ≈ 30.6°

c ≈ 25.1, A ≈ 27.6°, B ≈ 57.4°

c ≈ 25.1, A ≈ 31.6°, B ≈ 53.4°

Answer 2

law of cosines for this one
\[c^2=a^2+b^2-2ab\cos(C)\]
\[c^2=12^2+22^2-2\times 12\times 22\cos(95)\] and a calculator

Answer 3

i get \(c=25.962\) which i guess rounds to 26
http://www.wolframalpha.com/input/?i=c^2%3D12^2%2B22^2-2 \times+12\times+22\cos%2895%29

Answer 4

ok thank you!

Answer 5

now you can abandon the law of cosines, and move to the law of sines

Answer 6

\[\frac{\sin(A)}{a}=\frac{\sin(C)}{c}\]
\[\frac{\sin(A)}{12}=\frac{\sin(95)}{26}\]
\[\sin(A)=\frac{12\sin(95)}{26}\]
\[\sin(A)=.46\]
\[A=\sin^{-1}(.46)\]

Answer 7

i get \(27.37\)
http://www.wolframalpha.com/input/?i=arcsin%28 \frac{12\sin%2895%29}{26}%29

Answer 8

yw