calculus: use a(t)=-32 ft/s^2. how high will the ball go if the ball is thrown vertically upward from ground with initial velocity of 96 ft/s??
i got up to making the equation v(t)=-32t+96.... i have no idea what to do after that
I'll explain what the equations mean in words: v(t) is a function of time. It says that the velocity at time t is equal to v(t) now to solve this problem, we want to find the highest point the ball goes. but, do you agree that when the speed of the ball is equal to zero, it must either be midway in the air, reaching the maximum height, or landed on the ground (we want to ignore this case, since that would not be the highest point) So, in maths terms, you want to solve v(t) = 0 so, you need to solve 0 = -32t + 96 for t.
thanks
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