Question

how do you solve http://bamboodock.wacom.com/doodler/a1d5f65e-ab74-444b-ba6a-bb763d9a9fc8 ??? HELP

Answer 1

write 2^x as y
then 2^(-x) =... ?

Answer 2

-y?

Answer 3

no, \(\huge 2^{-x}=\frac{1}{2^x}=\frac{1}{y}\)
ok?

Answer 4

oh complex fractions. ;_;

Answer 5

does that appear in further mathematics courses? gawd I hope not

Answer 6

okay so what is my next step
?

Answer 7

so i have y+ (1/y)

Answer 8

ummm scream

Answer 9

so, did u get y+1/y = 6 ?

Answer 10

if yes, multiply y on both sides.

Answer 11

yess

Answer 12

so what Quadratic equation are you getting ?

Answer 13

so would it be like 2y =6y?

Answer 14

no, you get a Quadratic,
what do u get if you multiply 'y' to each term of
y+1/y = 6
?

Answer 15

y^2 = 6y...im lost

Answer 16

you get \(y^2+1=6y \implies y^2-6y+1=0\)
can you solve that quadratic ?

Answer 17

i got up to there...but how do you solve it?

Answer 18

i got it so i got
y=3±2√2

Answer 19

@hartnn

Answer 20

oh, sorry. i lost connection. :(