Question

An object is launched at 25 m/s from a height of 80 m. The equation for the height (h) in terms of time (t) is given by h(t) = -4.9t2 + 25t + 80. What is the object's maximum height?
Answer

Approximately 109 ft

Approximately 110 ft

Approximately 111 ft

Approximately 112 ft

Answer 1

@en28so I got 111

Answer 2

@en28so check my answer.

Answer 3

@abcabc got 111

Answer 4

@jazy well?!?!

Answer 5

@zepdrix I got 111

Answer 6

@abb0t 111

Answer 7

@LonelyandForgotten 111

Answer 8

@Hero Am I right?!

Answer 9

@karatechopper

Answer 10

Because I did it on my sheet... but correct huh?! no one respond..

Answer 11

@Hero I don't need the answer I have it, is it correct or no?!

Answer 12

Nvm I know i'm right weather or not good day sir.