Question

Long Division + Integral question [just a quick question]

Answer 1

Do you leave out the remainder 1?

Answer 2

actuall i figured out alread.. zepdrix, can u give me a short lesson on completing the square ...

Answer 3

dont remember any gr10 stuff @@

Answer 4

Why? Did you have to complete the square on this one? :o

Answer 5

no.. for partial fraction..

Answer 6

gimme couple mins, need to finish my sammich ^^ lol

Answer 7

haha sure, i'm not gonna sleep tonight anywayz :D

Answer 8

and thanks!

Answer 9

I'm confused :O Why would you be completing the square? Or you just need refresher on setting up partial fractions?

Answer 10

If we had an example it would help XD hah

Answer 11

I will show u the question then.
integral of x-9 / x^2 + 3x - 10

Answer 12

or is it not this one..

Answer 13

ok one sec c: gotta process it

Answer 14

yea, i think maybe not partial fraction, but there is definitely a ques that involves completing the square.. i need to search thru my assignments

Answer 15

I found it, uploading now~ one second

Answer 16

hmm

Answer 17

oo i like that little doodle pad :O lol

Answer 18

lol , i do all my work on my ipad haha, easier to find and organize

Answer 19

Are these like notes from a class, or you did this? :O

Answer 20

i did it.. is that wrong @@

Answer 21

No I'm just a little rusty on completing the square I guess :D hah!

I would have done it a little differently. I think it works out the same ... lemme see if this is accurate.

Answer 22

is your way easier and faster :D

Answer 23

:[ no it's probably worse lol

Answer 24

\[4x^2-4x-3 \quad = \quad 4(x^2-x)-3 \quad = \quad 4(x^2-x+\frac{1}{4}-\frac{1}{4})-3\]
\[4(x^2-x+\frac{1}{4})-1-3 \quad = \quad 4(x-\frac{1}{2})^2-4 \quad = \quad 4\left[(x-\frac{1}{2})^2-1\right]\]Which is pretty much the same thing you have, just without the 4 factored out.

Answer 25

Bahhhh I dunno XD

Answer 26

lol so to complete square, always take out the coefficient in front of the x^2?

Answer 27

That's how I would do it, otherwise it'll hurt my brain :O

You can take Half of the b term, and Square it, to complete the square.
I don't think you can do that when you have a coefficient on the leading term though..

Answer 28

so if it is 12x, then the last term will be 12 /2 = 6 ^2 = 36?

Answer 29

Yes.

Answer 30

And your factors would become b/2.
So in that example, you would have,

\[x^2+12x \quad = \quad x^2+12x+36-36 \quad = \quad (x+6)^2-36\]

Answer 31

oo, that's easy to remember!! thanks zepdrix !!