Question

math help

Answer 1

\[\large \sqrt{x+10}-9=-7\]Adding 9 to both sides gives us,\[\large \sqrt{x+10}=2\]Squaring both sides gives us,\[\large x+10=2^2\]Then finally subtract 10 from both sides to solve for x,\[\large x=4-10\]

Answer 2

Understand the process? The next one is a little bit tricky :O

Answer 3

-6?

Answer 4

Yes good c:

Answer 5

\[\large 4(3-x)^{4/3}-5=59\]Adding 5 to both sides, then diving by 4 gives us,\[\large (3-x)^{4/3}=16\]We'll raise both sides to the 3/4 power (Reciprocal of the power on x).\[\large \left((3-x)^{4/3}\right)^{3/4}=(16)^{3/4}\]

Answer 6

wait where did you get 3/4? fractions throw me off.;l

Answer 7

wait now i get it.

Answer 8

If you remember your rule of exponents, you'll see how that will simplify very nicely :) But yah it's kind of awkward raising something to the 3/4 power.

Answer 9

We have to be careful here though... Ummm... Since we had an EVEN power, and an EVEN root (the 4's), I think we need to be aware that there could be a negative solution to x that was lost during the squaring.\[\large \pm (3-x)=16^{3/4}\]

Answer 10

Lemme make sure I'm thinking about that correctly :D one sec.

Answer 11

i got 8 which isn't correct.

Answer 12

\[\large \pm (3-x)=16^{3/4}\]Taking the 4th root of 16 gives us,\[\large \pm (3-x)=2^3\]Which simplifies to,\[\large \pm(3-x)=8\]Let's apply the plus/minus to the other side,\[\large 3-x=\pm 8\]

Solving for x...\[\large x=3 \pm 8\]Is this the correct answer maybe? This one was a bit tricky..

Answer 13

these are the answer choices A.–5, 11
B.5
C.11
D.–11

Answer 14

Yes you need to do one tiny step to simplify it from where I was... :\

Answer 15

x=3+8
x=3-8

Answer 16

So A.? since 3+8=11 and 3-8=-5

Answer 17

Yes, I think so :)