Solve |2y - 2| = 15
Question 16 options: 8.5 -13 8.5 and -6.5 17 and -13
do you remember what the vertical lines mean :)?
\[|2y-2|=15\]\[(2y-2)^{2}=15^{2}\]\[4y^{2}-8y+4=225\]\[4y^{2}-8y-221=0\]\[y^{2}-2y-\frac{ 221 }{ 4 }=0\]\[y=\frac{ -b \pm \sqrt{b^{2}-4ac} }{ 2a }\]\[a=1\]\[b=-2\]\[c=\frac{ -221 }{ 4 }\]
Now just plug and chug.
Thanks
It's c.
How poopsiedoodle?
These aren't that hard, it's just asking you to plug in something for x and check to see if it's right, and then once you're done, remove the negative sign, if any.
But if you plug in -6.5 you dont get 15, if you do how?
2+ -6.5 = -13 -13-2=-15 |-15|=15
but isnt it multiply by 2
Yes. -6.5 = -13/2 The equation is\[|2y-2|=15\]\[|2 \times \frac{ -13 }{ 2 }-2|=15\]\[|-13-2|=15\]\[|-15|=15\]
OK thanks so much everybody!!! I appreciate it Ayvin and poopsiedoodle
Good night everyone thanks so much
You're welcome.
\(\Huge\text{♥}\)
Thanks so so so much
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