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Mathematics 14 Online
OpenStudy (anonymous):

Solve |2y - 2| = 15

OpenStudy (anonymous):

Question 16 options: 8.5 -13 8.5 and -6.5 17 and -13

OpenStudy (anonymous):

do you remember what the vertical lines mean :)?

OpenStudy (anonymous):

\[|2y-2|=15\]\[(2y-2)^{2}=15^{2}\]\[4y^{2}-8y+4=225\]\[4y^{2}-8y-221=0\]\[y^{2}-2y-\frac{ 221 }{ 4 }=0\]\[y=\frac{ -b \pm \sqrt{b^{2}-4ac} }{ 2a }\]\[a=1\]\[b=-2\]\[c=\frac{ -221 }{ 4 }\]

OpenStudy (anonymous):

Now just plug and chug.

OpenStudy (anonymous):

Thanks

OpenStudy (poopsiedoodle):

It's c.

OpenStudy (anonymous):

How poopsiedoodle?

OpenStudy (poopsiedoodle):

These aren't that hard, it's just asking you to plug in something for x and check to see if it's right, and then once you're done, remove the negative sign, if any.

OpenStudy (anonymous):

But if you plug in -6.5 you dont get 15, if you do how?

OpenStudy (anonymous):

2+ -6.5 = -13 -13-2=-15 |-15|=15

OpenStudy (anonymous):

but isnt it multiply by 2

OpenStudy (anonymous):

Yes. -6.5 = -13/2 The equation is\[|2y-2|=15\]\[|2 \times \frac{ -13 }{ 2 }-2|=15\]\[|-13-2|=15\]\[|-15|=15\]

OpenStudy (anonymous):

OK thanks so much everybody!!! I appreciate it Ayvin and poopsiedoodle

OpenStudy (anonymous):

Good night everyone thanks so much

OpenStudy (anonymous):

You're welcome.

OpenStudy (poopsiedoodle):

\(\Huge\text{♥}\)

OpenStudy (anonymous):

Thanks so so so much

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