Given: cos(theta) = -4/5 , sin x = -12/13, theta is in the third quadrant, and x is in the fourth quadrant; evaluate tan(1/2)(theta) -3 3 1/3
@dpaInc
So I know that tan = 3/4 (from the last problem) but do I just multiply that by 1/2? Because that would make it 3/8 but that's not a choice... What do I do?
@saifoo.khan
is this the question: \(\large tan(\frac{\theta}{2})= \) ????
Yes
ok.. do you know the half-angle formula for tangent?
nvmd... i'll put it up..
\(\huge tan(\frac{\theta}{2})=\pm\sqrt{\frac{1-cos\theta}{1+cos\theta}} \)
now you already have the value for cos(theta). what was it???
Oh right right right!! I forgot the formulas part.. & cos(theta)=3/4
the problem says cos(theta) = -4/5
Whoops, that was tan.. Embarassing.
sawright... :)
So would that give you 9?
so.... \(\large tan(\frac{\theta}{2})=\pm\sqrt{\frac{1-(-4/5)}{1+(-4/5)}} \) simplify this.... then we'll determine which one it is... (positive or negative)
the top would be 9/5 and the bottom 1/5 then you would get 9 & you have to sqrt it. So it would be +/- 3
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