Ask
your own question, for FREE!
Mathematics
12 Online
How do you find the limit of this problem? lim (sqrt(x^2 + ax) - sqrt(x^2 +bx) x-->infinity
Still Need Help?
Join the QuestionCove community and study together with friends!
\[\lim_{x \rightarrow \infty}(\sqrt{x^{2}+ax}-\sqrt{x^2+bx})\]?
yes
I believe it would be Infinity if a>b and -Infinity if a<b
can you please explain how you got to that answer?
Ahh, I was wrong. Ignore my first answer. \[\lim_{x \rightarrow \infty}\sqrt{x}(\sqrt{x+a}-\sqrt{x+b})\]\[\lim_{x \rightarrow \infty}\sqrt{x} \times \frac{ (\sqrt{x+a}-\sqrt{x+b}) \times (\sqrt{x+a}+\sqrt{x+b}) }{ \sqrt{x+a}+\sqrt{x+b} }\]\[(a-b) \times \lim_{x \rightarrow \infty}\frac{ \sqrt{x} }{ \sqrt{x+a}+\sqrt{x+b} }\]\[\frac{ a-b }{ 2 }\]
Can't find your answer?
Make a FREE account and ask your own questions, OR help others and earn volunteer hours!
Join our real-time social learning platform and learn together with your friends!
Join our real-time social learning platform and learn together with your friends!
Latest Questions
VERNEISH:
Two objects are moving along separate linear paths where each path is described by position, d, and time, t.
Maci:
what are the best stock apps for people who want to start investing?
Twaylor:
genuienly how do i get better self control i keep watcing youtube and theres this
IzzyCookie:
|dw:1792074056138:dw| Uhm, I don't know where to ask this, but I'm in college welding at my community college, and I need help learning vertical welding for
thehearken:
not sure if this is considered spam, im sorry if it is, but does anyone have tips
16 hours ago
0 Replies
0 Medals
4 days ago
3 Replies
2 Medals
1 week ago
3 Replies
0 Medals
2 days ago
9 Replies
1 Medal
1 week ago
2 Replies
1 Medal