One antifreeze solution is 20% alcohol. Another antifreeze solution is 12% alcohol. How many liters of each solution should be combined to make 15 liters of antifreeze that is 18% alcohol?
Can you help @RadEn
Can you help @CalebBeavers
Im thinking one equation would be .20x+.12y=.18*15 and then one for the total amount x+y=15 now you have two simultaneous equations
Let x = the amount of liters of the 20% alcohol solution Let y = the amount of liters of the 12% alcohol solution Then the total amount of liters of antifreeze is x + y = 15 The total percentage of alcohol solution in the combined solution is .20x + .15y = 2.7
Now conduct the following steps: 1. Multiply the first equation by .20 2. Subtract the second equation from the first 3. Solve for y 4. Then solve for x
Thank you @CalebBeavers and @Hero!!
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