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Mathematics 13 Online
OpenStudy (anonymous):

f(x) = x^2 + x+1 compute the ratio f(x+h) - f(x)/h can someone show me the steps for this one its really confusing me.

OpenStudy (raden):

is it limit ?

OpenStudy (anonymous):

no no I just started learning this stuff theres no limit things and higher stuff involved

OpenStudy (anonymous):

First solve for f(x+h): (x+h)^2 + (x+h) + 1 Then plug it into that second part, the formula: [(x+h)(x+h)+x+h+1-(x^2+x+1)]/h

OpenStudy (anonymous):

Now foil it out and distribute the negative: [x^2 + 2xh + h^2 + x + h + 1 - x^2 -x -1]/h Combine like terms: [2xh + h^2 + h]/h

OpenStudy (anonymous):

Pull out the h: [h(2x+h+1)]/h Reduce: 2x+h+1

OpenStudy (anonymous):

And that's the derivative. Were you given x=something?

OpenStudy (anonymous):

no I dont think so.

OpenStudy (anonymous):

Ok, then I think that's it.

OpenStudy (anonymous):

thats the whole problem that I wrote up there. I dont understand how u plug in x^2+x+1 into the f(x+h) part

OpenStudy (anonymous):

it is derivative, but it a long method

OpenStudy (anonymous):

sowwy...and p->q all you do is just plug in (x+h) for every instance of x.

OpenStudy (anonymous):

I thought it was the otherway around like whatever they say let f of x is u plug that into the problem they gave u

OpenStudy (anonymous):

OOO wait I got it it just clicked. What you said is basically like f(1)

OpenStudy (anonymous):

cool cool ty ty

OpenStudy (anonymous):

winterfez can you explain the shortcut?

OpenStudy (anonymous):

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