Question

Find t he domain and range: f(x) = x^2 -4x +3
answer D:(-infinity, infinity) R:(-1, infinity)

Answer 1

\[\large f(x)=x^2-4x+3 \qquad \rightarrow \qquad f(x)=x^2-4x+4-1\]
\[\large f(x)=(x-2)^2-1\]-1 is the lower boundary for your range? Hmm yah looks good! :D

For some reason your domain bracket looks like an angry smiley to me,\[D:(-\]

Answer 2

so how do i get domain and range @zepdrix

Answer 3

Oh i see, you weren't just checking your answer, you need to get it :) my bad. ok one sec.

Answer 4

@dpaInc u explain whyyyy D:

Answer 5

lol

Answer 6

You prolly has been words than my mouf D: with the "rational powers" and uhhh "real coefficients" or blah blah somethign like that D:

Answer 7

See how I completed the square and put the parabola in standard form fay? :O Does that part make sense?

Answer 8

i don't see anything wrong... your range is [-1, infinity)

Answer 9

my graphing calculator just ran out of batteries rite now so -.- yeah..

Answer 10

She pasted the answer key plank, she wants to know how to get it.

Answer 11

no batteries!?? so you have to do some ACTUAL work?? :O OH NO!

Answer 12

yes what u did above i get but how do i find domain and rangestilll

Answer 13

unless i can find a free online graph. calculator on google?:p

Answer 14

So remember what a parabola looks like?
In standard form, if we were to graph this, we would see that the parabola opens UPWARD because there's no negative in front of the square term.

Anddd it's vertex is at the point (2,-1)

Answer 15

here's the best online GC: https://www.desmos.com/calculator

Answer 16

Ooooo that looks fun! :O

Answer 17

can it interpret latex? :X

Answer 18

wait so just by looking at my graphing calculator i can find domain and range? ^^

Answer 19

@dpaInc thx man/bro :33