Finding the zeros of:
f(x)=-2x^4+2^3+6x^2+18

Question

Finding the zeros of:
f(x)=-2x^4+2^3+6x^2+18

anonymous · Answer

At first I changed it so I have a positive 2. Then I found the factors of -18 and 2.

anonymous · Answer

i assume it is 
$$f(x)=-2x^4+2x^3+6x^2+15$$ right?

anonymous · Answer

actually + 18 at the end...but yes

anonymous · Answer

unless the problem has been cooked up to make the zeros rational (this one hasn't) there is no quick or easy method to finding the zeros of a fourth degree polynomial. there is in fact a formula, but it fills up an entire page. i would use wolfram or some other technology to try and locate them. you will not do othis by hand http://www.wolframalpha.com/input/?i=-2x^4%2B2x^3%2B6x^2%2B18

anonymous · Answer

geez i hope this is not on the test =(