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Finding the zeros of: f(x)=-2x^4+2^3+6x^2+18
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At first I changed it so I have a positive 2. Then I found the factors of -18 and 2.
i assume it is \[f(x)=-2x^4+2x^3+6x^2+15\] right?
actually + 18 at the end...but yes
unless the problem has been cooked up to make the zeros rational (this one hasn't) there is no quick or easy method to finding the zeros of a fourth degree polynomial. there is in fact a formula, but it fills up an entire page. i would use wolfram or some other technology to try and locate them. you will not do othis by hand http://www.wolframalpha.com/input/?i=-2x^4%2B2x^3%2B6x^2%2B18
geez i hope this is not on the test =(
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