Ask your own question, for FREE!
Mathematics 14 Online
OpenStudy (anonymous):

Assume the function f is such that f'' (x) > 0 for all values of x. Which one of following statement is true about f?

OpenStudy (anonymous):

see picture

OpenStudy (anonymous):

A can't be right think of \(e^x\)

OpenStudy (anonymous):

I know it's not A or B

OpenStudy (anonymous):

i guess it can't be C either,again think of \(e^x\) , no zeros, no critical point

OpenStudy (anonymous):

and similarly D can''t be right, for the same reason that leave E

OpenStudy (anonymous):

of course if the critical number exists, and if \(f''>0\) this means it must be a local min i guess it is also true that there can be at most one, since if \(f''>0\) that means \(f'\) is always increasing, so it cannot be zero more then once

OpenStudy (anonymous):

how do u know that f behaves like e^x ?

OpenStudy (anonymous):

the only info u have is f is concave up.. but it still can mean it crosses the xintercept right @satellite73

OpenStudy (shubhamsrg):

E is the correct ans..see,, it is given that rate of change of slope is always positive.. which means slope must be negative somewhere and is increasing as x increasing, hence it'll go from -ve to 0 to +ve,,which means minima..

OpenStudy (anonymous):

I do understand there is a minima, and slope is always increasing oh wait, i get it since there is a minima, that means f'(x) = 0 , which means 1 critical point , is that right?

OpenStudy (anonymous):

no one says it crosses the \(x\) axis

OpenStudy (anonymous):

E says it has AT MOST one critical point, and IF it has one, it is a min

OpenStudy (anonymous):

yea, i'm keep mixing up root and ciritical pt :/

OpenStudy (anonymous):

again \(e^x\) is a good example it has not critical point, and never crosses the \(x\) axis it was an "if" statement

OpenStudy (anonymous):

btw the critical point if it exists must be root of the derivative, it cannot be where the derivative is undefined writing \(f''<0\) assumes that \(f''\) exists for all \(x\) and therefore \(f'\) exists for all \(x\) as well

OpenStudy (anonymous):

@satellite73 hey, just a quck quesion. If f'' exist, f' cant be undefined rght

OpenStudy (anonymous):

yes that is right if \(f''\) exists then \(f'\) must not only be defined, it must be continuous as well

OpenStudy (anonymous):

ok thanks!

OpenStudy (anonymous):

now i have a question

OpenStudy (anonymous):

what drink are you making?

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!