Question

Factor 4x^2 - 20x +25

Answer 1

You could use the quadratic formula to help you factor it

Answer 2

@ChmE Are you sure ?

Answer 3

it will get you the 2 solutions then you could just setup the ( )( ) form from there.

Answer 4

@ChmE Sorry to say you are wrong.

Answer 5

a=4 b=-20 c=25

Answer 6

http://www.purplemath.com/modules/quadform.htm

Answer 7

when i worked it out it is
(4x-5)(x-5) but checking it, it doesnt work

Answer 8

@ChmE

Do you know what the standard form should be ?

It should be

\[ax^2+bx+x=0\]

Answer 9

Not

\[ax^2+bx+x\]

Answer 10

\[20 \pm \sqrt{20^2-4(4)(25)} \over 2(4)\]\[20 \pm \sqrt{400-400} \over 8\]\[{20 \over 8}={5 \over 2}\]This will be the only solution, but will happen twice

(x-(5/2))(x-(5/2)) times 2 to get rid of the fraction
(2x-5)(2x-5)

This could have been done by factoring but you could use the quadratic formula to help you if you couldn't figure it out

Answer 11

Doing it the wrong way does not help when you have to show the solution to the teacher.

Answer 12

Factoring:

4x^2 - 20x + 25

Split the middle term

4x^2 - 10x - 10x + 25

Group the left 2 terms and the right two terms, and factor them

2x(2x - 5) + -5(2x-5)

factor out the (2x-5)

(2x-5)(2x-5)

Answer 13

I don't know what your problem is @hba , but either get a purple border around your picture or shut up

Answer 14

I am just trying to show him the right way,stop being rude.

Answer 15

There is no "right", there are two possible ways, whatever is easier for that person is the right way for them.

Answer 16

@ChmE But that is not the correct way,

you are not understanding that.