Choose the slope-intercept equation of the line that passes through the point shown and is parallel to the line shown below.
y = 3x – 14 y = 1/3x + 2 y = –3x + 22 y = –1/3x + 8
It's y = 1/3x + 2, right?
Take any two points on the slope,find rise run and then put it in the equation and find it.
So if I take (0,-3) and (3,2), I just add them into X and Y of the equations?
First find slope and then put it in the equation
The slope is 1/3?? Right?
No m=y2-y1/x2-x1
I got 5/3??
Yeah right :) Now put it in the equation :)
Would I out that under the point slope formula as in y-y1=m(x-x1) and then put that to a slope intercept form?
judging from the line, the slope of the given graph is 1/3, not 5/3 if the new line passes through (6, 4), then use the point-slope formula with that point and the slope 1/3 y - 4 = (1/3) ( x - 6 ) y = (1/3) x - 2 + 4 y = (1/3) x + 2
thank you so much!!
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