domain and range of the function in interval notation
f(x)=sqrtx-1

Question

domain and range of the function in interval notation
f(x)=sqrtx-1

anonymous · Answer

$$f(x)=\sqrt{x-1}$$

anonymous · Answer

you cannot have negative squareroot, so set $$x-1 \ge0$$, then solve for x, so we'll have $$x \ge1 $$. so domain is anything greater than 1, [1,infinity)

anonymous · Answer

i think domain is $$(1,\infty) and the range is [-1,\infty]$$

anonymous · Answer

and the range is going to be ??

anonymous · Answer

0 to infinity. why u think range is from -1 to infinity?

anonymous · Answer

because of the problem being x-1 I thought that would make it -1 to infinity but as you see I am wrong and do not get this at all

anonymous · Answer

would the thing be [ or( before the 0

anonymous · Answer

that's have nothing to do with range, range is more about y. What's the lowest y values?

anonymous · Answer

[0, infinity), because 0 is included, you can take sqrt[0] right?

anonymous · Answer

oh  I am going to be so glad when today is over, today is my last class for my aa and it is driving me crazy. I still have 21 questions to go

anonymous · Answer

lol, goodluck