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What is the equation of the axis of symmetry of the quadratic equation y = 2(x – 4)2 + 7?
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Do you mean\[y=2(x-4)^{2}+7\]
\(\large\text{if you help me with this, I will love you forever.}\) And yes.
Ok
So you know that vertex form is \[y=a(x-h)^{2}+k\] and that (h,k) is the same as (x,y) right?
Yes.
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Well the axis of symmetry is just x. And since x is 4 in this, the equation of the axis of symmetry is x=4
Do you understand?
Kinda. The part I don't get is the (x-h)^2 part. I forgot the rule for squaring things inside of parentheses ._.
oh wait. I feel kinda dumb now.
don't even need that. Sorry for being a dingus.
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o.O
So do you understand?
Yeah \(\Huge{:3}\)
Ok ^-^
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