Question

please help me everyone . what is the derivative of:
f(t)=20[1-cos^2(t/1000pi)]

Answer 1

Yes that would be the case if pi was in the numerator, but I think you said pi was in the denominator though?

Answer 2

\[f(t)=20[1-\cos^2(\frac{ t }{ 1000\pi })\]

like that ^

Answer 3

\[\frac{ \sin(\frac{ x }{ 500\pi }) }{ 50\pi }\]

is this your answer?

Answer 4

\[f(t) = 20 - 20\cos ^{2}(t/(1000\pi))\]
\[f'(t) = 0 - 20 * 2\cos (t/(1000\pi)) * -\sin (t/(1000\pi)) * (1/(1000\pi))\]
\[f`(t) = 20/1000\pi * 2\cos(t/1000\pi)*\sin(t/1000\pi)\]
Use identity sin (2x) = 2sinxcosx
\[f'(t) = 1/50\pi * \sin (2*t/1000\pi)\]

Answer 5

that acually looks right to me. ^

Answer 6

You can also check your answers by punching the equations into wolframalpha.com

Answer 7

beautiful, thank you.

Answer 8

No problem, good luck!