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Mathematics 16 Online
OpenStudy (anonymous):

4/3-squareroot of 2

OpenStudy (anonymous):

Do You Expand It?

OpenStudy (anonymous):

i have no idea this is so hard

OpenStudy (poopsiedoodle):

Yeah, what are supposed to do with it? simplify?

OpenStudy (anonymous):

yea i guess

OpenStudy (poopsiedoodle):

Is this a multiple choice question?

OpenStudy (anonymous):

|dw:1355803901479:dw|

OpenStudy (anonymous):

oh wow.

OpenStudy (anonymous):

no its not multiple choice

OpenStudy (poopsiedoodle):

OH.

OpenStudy (poopsiedoodle):

https://www.wolframalpha.com/input/?i=4%2F%283-%E2%88%9A2%29 *

OpenStudy (poopsiedoodle):

What are the instructions for the question?

OpenStudy (anonymous):

i have 6 more of these questions....... I'm not gonna fish in time for christmas

OpenStudy (anonymous):

it doesn't have any instructions it jet says the problem

OpenStudy (anonymous):

You have to rationalize the denominator

OpenStudy (anonymous):

how

OpenStudy (anonymous):

okay, you have \[\frac {a} {b- \sqrt{c}}\], you don't want to have roots on the denominator,so, you multiply by 1 in this form \[\frac {a} {b- \sqrt{c}}\ \times \frac {b+\sqrt{c}} {b+\sqrt{c}}\] and you'll obtain \[\frac {a \times (b+ \sqrt{c})} {b^2-c} \] Got it?

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