Question

Evaluate each expression.

a. log₂32
b. log(.0001)
c. lne⁻³
d. log₄1

Answer 1

You have to use the properties, for example, in a, your 32 is a power of 2, in b the same, 0,0001 is a power of 10, ln=log_e and in d, there's only one way to obtain 1 in a number that is not 1 xD (a^0=1)

Answer 2

how do i do that?

Answer 3

okay, if you have, for example log 100 it is 2, right?, because 10^2=100, that's because of logarithmic function definition
when you have
\[a^x=b\] that's equal to
\[\log_a{b}=x \]
so, in a you have
\[\log_2 {32}=\log_2 {2^5}\]
that means that x=5, got it?

Answer 4

oh okay got that

Answer 5

i just dont understand how to find the final answer

Answer 6

the "x" in ths case is the final answer

Answer 7

so for a. the answer is x=5?

Answer 8

the answer is 5, i used the x to compare it with the definition

Answer 9

oh okay great, thanks!! how about b?

Answer 10

i got -4 for b

Answer 11

@Umangiasd

Answer 12

goood

Answer 13

i didn't get c

Answer 14

or d :( those two confuse me

Answer 15

c is the easier one
\[\ln b=\log_e{b} \]
that means
\[\ln e^{-3}= \log_e {e^{-3}}\]

Answer 16

so is logee−3 the final answer?

Answer 17

the way you typed it of course

Answer 18

nope, that means that is equivalent, now if
\[\log_2 {2^5} =5\]
then
\[\log_e {e^{-3}}=-3\]
got that?

Answer 19

ohh okay so then it would be -3?

Answer 20

ohh okay i sort of understand now

Answer 21

;)

Answer 22

how about the last one

Answer 23

@Umangiasd

Answer 24

4^0=1, then your answer is?

Answer 25

1? @Umangiasd

Answer 26

nope, look at what you have in the question.