Question

3x+2 over (x-4)(x+4)(x-4)

Answer 1

are you looking for the x and y ?

Answer 2

just x

Answer 3

ok

Answer 4

What are you trying to do live? We have no equality sign, so we can't solve for x.

Are you trying to simplify it?
Or just expand out the brackets? :O

Answer 5

yes trying just to simplify

Answer 6

this is what i got , i am confused on this question. -62 + 19x + 4x2 + -1x3 = 0

Answer 7

\[\large \frac{3x+2}{(x-4)(x+4)(x-4)}\]Is this what the problem looks like?

Answer 8

yes

Answer 9

Let's deal with just 2 of the brackets first,
Notice how we have (x+4)(x-4)
Those are called "conjugates", they're the SAME except with the opposite sign between them. Here is the rule for multiplying conjugates,\[\huge (a+b)(a-b)=a^2-b^2\]Applying this to our problem gives us,\[\huge (x+4)(x-4)=x^2-4^2\]Understand that part ok?

Answer 10

yes

Answer 11

That changes our equation to,\[\huge \frac{3x+2}{(x-4)(x^2-4^2)}\]
Now to further expand, we just FOIL out the bottom.

Answer 12

can we box it?, i never was taught the foil method

Answer 13

box it? :) how does that work?

Answer 14

Oh cool :D

Answer 15

So if we square the 4, we have, \[\huge (x-4)(x^2-16)\]and we can do the box method from here

Answer 16

k

Answer 17

Are you putting the square terms across the top? or along the side? I just wanna make sure I do the same :X