Question

Solve: 5y^2-6=7y

Answer 1

you want to get it in the form

ax^2 + bx + c = 0

Answer 2

Then you can either factor or use the quadratic

Answer 3

follow what Chme is suggesting (if u don't get then check ur answer with th following)
5y^2-7y-6=0
or 5y^2-10y +3y -6 =0
or 5y(y-2) +3(y-2) =0
or (5y+3)(y-2) =0
or y=2 or y=-5/3

Answer 4

What do I do after 5y^2-7y-6=0?

Answer 5

How do I get -3/5, 2?

Answer 6

http://www.purplemath.com/modules/quadform.htm

Answer 7

matricked showed you factoring. The hidden secrets in his steps is what he didn't show you. He split the center term but how did he know to split it into 10 and 3?

The first term's coefficient is 5. The only way to get this is a 1 and a 5. The last term is -6, it has factors of -1,1,-2,2,-3,3,-6, 6. We need to think of a way that 5 can multiply against one of the factors and 1 to multiply against one of the factors and when they are added to get 7.

-2 times 5 is -10 plus (3 times 1) is -7 check. That's where those came from. Then he grouped the left 2 terms and the right 2 terms and factored what they had in common out. And it works out perfectly that they now have another thing in common, its just in the form of (x + b). So they factored that out and got (x + a)(x + b), of course with the correct signs and numbers

Answer 8

and when they are added to get -7****