Question

(cos pi/4 - tan pi/4)^2

Answer 1

Find the value of :

\[\cos(\frac{\pi}{4}) = ??\]

Answer 2

@yasmin95 u know the value of cos and tan

Answer 3

Then find :

\[\tan(\frac{\pi}{4}) = ??\]

Answer 4

(1/square root 2 - 1)^2

Answer 5

Then use :

\[(a-b)^2 = a^2 + b^2 - 2ab\]

Answer 6

how?

Answer 7

Yes good..

Go ahead now..

Answer 8

\[(\frac{1}{\sqrt{2}} - 1)^2 \implies \frac{(1 - \sqrt{2})^2}{(\sqrt{2})^2}\]

Answer 9

In the numerator, use the above formula..

Answer 10

how did u get the above step ?

Answer 11

This is by using LCM or LCD concept:

\[\frac{1}{\sqrt{2}}- 1 \implies \frac{1}{\sqrt{2}}- \frac{\sqrt{2}}{\sqrt{2}} \implies \frac{1 - \sqrt{2}}{\sqrt{2}}\]

Answer 12

okay :)

Answer 13

i solved it thanks !!

Answer 14

More explanation??

Answer 15

Okay..

You are welcome dear..