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x 2 + y 2 + 6x − 8y + 8 = 0 represents a circle. Find its centre and show that its radius is √ 17.
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center is (-3,4) and radius is \[\sqrt{17}\]
many thanks. please could you show me how you got this if possible
circle: (x-a)^2 +(y-b)^2=R^2 <=> x^2+y^2-2ax-2yb+a^2+b^2-R^2=0
with center (a,b) radius R
in case: -2a=6 ->a=-3 -2b=-8 ->b=4 a^2+b^2-R^2=8 -> R=sqrt(17)
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thank you that makes some sense. thank you for your help
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