Question

In the figure, AC is a diameter of the circle with length 20 cm and BC=12 cm.
(a) Find AB. [16 cm]
(b) Show that triangle ABC similar to triangle AOP. [proved]
(c) Hence find AP and OP. ←I have problem with this....

Answer 1

since triangles are similar, their sides will be proportional

Answer 2

AO =10, right ?

Answer 3

yes

Answer 4

so, u only need , either AP or OP., then pythagoras....

Answer 5

AP/20=OP/12 ?

Answer 6

and what about third side ?

Answer 7

=AO/AB

Answer 8

and u know both AO and AB

Answer 9

AP/20=10/16

Answer 10

yes.

Answer 11

AP=12.5 cm and OP=7.5 cm?

Answer 12

thank you:)

Answer 13

welcome ^_^

Answer 14

would you kindly help me with another question?

Answer 15

In the figure, two circle meet at P and Q. APB, ARSD and CQD are straight lines. If angle APR=70, find angle SQC.

Answer 16

AB and CD would be parallel, right ?

Answer 17

no

Answer 18

@sauravshakya , plz give this a try...

Answer 19

sorry for misleading you....

Answer 20

Hint: Join PQ

Answer 21

ABQ~RBP and ACR~QCS,
AB * BP = CA * CS
(c) If PS//BC, find BP:CS.