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Mathematics 4 Online
mathslover (mathslover):

Prove that if the 3 altitudes of a triangle are equal then the triangle is equilateral. See attachment

mathslover (mathslover):

I tried to do this and have got so far that AB = AC

mathslover (mathslover):

@ParthKohli

mathslover (mathslover):

@experimentX

mathslover (mathslover):

I took following triangles :ABF and AEC by AAS I got both of these triangles congruent and therefore by CPCT AB = AC

mathslover (mathslover):

(CPCT = Congruent Parts of Congruent Triangles are equal)

OpenStudy (anonymous):

That idea should work to get that AB=BC as well.

mathslover (mathslover):

So far , we have got ABC as isosceles. Now, I took triangle ABC and AFC both of these triangles are congruent by RHS BF = FC ( by CPCT ) therefore F is mid point of BC an AF is median and altitude also Therefore , this is the property of an equilateral triangle , so ABC is an equi. triangle

mathslover (mathslover):

Is this correct?

mathslover (mathslover):

You mean to take ABE and BEC triangles @joemath314159 ?

OpenStudy (anonymous):

yep. and do exactly what you did with the other triangles again.

mathslover (mathslover):

I meant this : ADC and ABD in the above comment.

mathslover (mathslover):

OK wait..

mathslover (mathslover):

I think I had tried that earlier but I didnt' get any favorable result , wait let me do it again

OpenStudy (anonymous):

there are many combinations you could take. The pair I see is triangles BEC and BDA.

mathslover (mathslover):

Oh yes that will work ... BEC and BDA .. this gives some output to me.

mathslover (mathslover):

Thanks a lot @joemath314159 for your help .. Might gonna work in more concentration for me..

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