Question

Help Plz?
Verify the identity.cot (θ - π/2 )= - tanθ

Answer 1

You can write :

\[\cot(\theta - \frac{\pi}{2}) = \cot(-(\frac{\pi}{2} - \theta))\]

Answer 2

Now :

\[\cot(- \theta) = - \cot(\theta)\]

Answer 3

So now by using this what have you got??

Answer 4

idk im kinda lost

Answer 5

This is not the answer, I am just saying to use that formula there..

Answer 6

o ok

Answer 7

Where??

Answer 8

so what do I do next

Answer 9

Where??

Answer 10

Then use:

\[\cot(\frac{\pi}{2} - \theta) = \tan(\theta)\]

Answer 11

ok

Answer 12

Now show me all the steps..

Answer 13

ok

Answer 14

cot ( theta - pi / 2 )= cos ( theta - pi / 2 ) / sin ( theta - pi / 2 )

cos ( theta - pi / 2 )= cos(theta) cos (pi/2) + sin(theta) sin (pi/2)
= cos(theta) (0) + sin(theta) (1)
= sin(theta)

sin ( theta - pi / 2 )= sin(theta) cos(pi/2) - cos(theta) sin(pi/2)
= sin(theta) (0) - cos(theta) (1)
= -cos(theta)
so you get,
cot ( theta - pi / 2 )= sin(theta) / -cos(theta)
cot ( theta - pi / 2 )= -tan(theta)

Answer 15

so u have the solution.

Answer 16

ok so I have my answer now right

Answer 17

This one is right....

Answer 18

ok thanks so should I write this whole thing as my answer or can I just write
cot ( theta - pi / 2 )= sin(theta) / -cos(theta)
cot ( theta - pi / 2 )= -tan(theta)

Answer 19

whole thing.

Answer 20

ok thanks